colorado_hick
Well-known member
working on a synth build, I wanted to have the ability to quickly choose a different sound or a different octave so I decided I would get potentiometers that have 11 dentants (clicking points). That way I can switch between 11 different scenarios with just using one analog pin. It just took a little experimenting to get the analog read ranges right for the 11 different positions and then it worked great with the breadbox prototype. As you can probably predict I have one side going to the +, one side going to the -, and the middle wiper going to an analog pin. The + and - are in parallel on the same wire.
Now that I have soldered everything up and have to of them I am getting some unusual readings out of one of the pots. Yet when I disconnect everything and measure ohms at the different clicks it seems right on with the other one.
I am wondering is there some sort of voltage bleed that would impact the voltage measurements coming off the potentiometers when they were wired close together? It is almost like changing one potentiometer impacts the measurement on the other one which really confuses me. Do I need some diodes or something to keep voltage from leaking on to the ground when the pot is cranked down? Or should I just disconnect that side of the pot from the - and ground it to its self like I would on an audio pot in an electric guitar?
It is a simple circuit, with one 3.2v LED as a power-on light and 14 momentary contact switches for keys.
Here is my function that takes the analog pin as an input and returns a value 0-10 that I use as a switch:
Now that I have soldered everything up and have to of them I am getting some unusual readings out of one of the pots. Yet when I disconnect everything and measure ohms at the different clicks it seems right on with the other one.
I am wondering is there some sort of voltage bleed that would impact the voltage measurements coming off the potentiometers when they were wired close together? It is almost like changing one potentiometer impacts the measurement on the other one which really confuses me. Do I need some diodes or something to keep voltage from leaking on to the ground when the pot is cranked down? Or should I just disconnect that side of the pot from the - and ground it to its self like I would on an audio pot in an electric guitar?
It is a simple circuit, with one 3.2v LED as a power-on light and 14 momentary contact switches for keys.
Here is my function that takes the analog pin as an input and returns a value 0-10 that I use as a switch:
Code:
int checkDentent(int readPin) {
int dententPot1 = analogRead(readPin);
Debugln(dententPot1);
// Debug(readPin);
// Debug(" ");
// Debugln(dententPot1);
if (dententPot1 < 10 ) {
return 10;
}
else if ( dententPot1 < 100 ) { //48
return 9;
}
else if ( dententPot1 < 200 ) { //165
return 8;
}
else if (dententPot1 < 310 ) { //285
return 7;
}
else if (dententPot1 < 440 ) { //400
return 6;
}
else if (dententPot1 < 580 ) { //512
return 5;
}
else if (dententPot1 < 700 ) { //620
return 4;
}
else if (dententPot1 < 800 ) { //735
return 3;
}
else if (dententPot1 < 910 ) { //859
return 2;
}
else if ( dententPot1 < 1000 ) { //980
return 1;
}
else { //1023
return 0;
}
}